Exponentiation operator in Swift

6 Solutions Collect From Internet About “Exponentiation operator in Swift”

There isn’t an operator but you can use the pow function like this:

return pow(num, power)

If you want to, you could also make an operator call the pow function like this:

infix operator ** { associativity left precedence 170 }

func ** (num: Double, power: Double) -> Double{
    return pow(num, power)
}

2.0**2.0 //4.0

If you happen to be raising 2 to some power, you can use the bitwise left shift operator:

let x = 2 << 0    // 2
let y = 2 << 1    // 4
let z = 2 << 7    // 256

Notice that the ‘power’ value is 1 less than you might think.

Note that this is faster than pow(2.0, 8.0) and lets you avoid having to use doubles.

For anyone looking for a Swift 3 version of the ** infix operator:

precedencegroup ExponentiationPrecedence {
  associativity: right
  higherThan: MultiplicationPrecedence
}

infix operator ** : ExponentiationPrecedence

func ** (_ base: Double, _ exp: Double) -> Double {
  return pow(base, exp)
}

func ** (_ base: Float, _ exp: Float) -> Float {
  return pow(base, exp)
}

2.0 ** 3.0 ** 2.0    // 512
(2.0 ** 3.0) ** 2.0  // 64

I did it like so:

operator infix ** { associativity left precedence 200 }

func ** (base: Double, power: Double) -> Double {
    return exp(log(base) * power)
}

There isn’t one but you have the pow function.

Like most of the C-family of languages, there isn’t one.