How do I check in Swift if two arrays contain the same elements regardless of the order in which those elements appear in?

3 Solutions Collect From Internet About “How do I check in Swift if two arrays contain the same elements regardless of the order in which those elements appear in?”

Swift 3, 4

extension Array where Element: Comparable {
    func containsSameElements(as other: [Element]) -> Bool {
        return self.count == other.count && self.sorted() == other.sorted()
    }
}

// usage
let a: [Int] = [1, 2, 3, 3, 3]
let b: [Int] = [1, 3, 3, 3, 2]
let c: [Int] = [1, 2, 2, 3, 3, 3]

print(a.containsSameElements(as: b)) // true
print(a.containsSameElements(as: c)) // false

you can do something like this:

  array1.sortInPlace()
  array2.sortInPlace()

  print(array1,array2)

  if array1 == array2 {
    print("equal")
  } else {
  print("not equal") 
  }

and if don’t want change origional array we can do

 let sorted1 = array1.sort()
 let sorted2 = array2.sort()

  if sorted1 == sorted2 {
    print("equal")
  }else {
    print("not equal")
  }

Create function to compare them:

func containSameElements(var firstArray firstArray: [String], var secondArray: [String]) -> Bool {
    if firstArray.count != secondArray.count {
        return false
    } else {
        firstArray.sortInPlace()
        secondArray.sortInPlace()
        return firstArray == secondArray
    }
}

Then:

var array1 = ["a", "a", "b"]
var array2 = ["a", "b", "a"]

var array3 = ["a", "b", "c"]
var array4 = ["b", "c", "a", "d"]

print(containSameElements(firstArray: array1, secondArray: array2)) //true
print(containSameElements(firstArray: array3, secondArray: array4)) //false
print(array1) //["a", "a", "b"]
print(array2) //["a", "b", "a"]
print(array3) //["a", "b", "c"]
print(array4) //["b", "c", "a", "d"]