Negate #available statement

3 Solutions Collect From Internet About “Negate #available statement”

I use a guard for this:

guard #available(iOS 8.0, *) else {
    // Code for earlier OS
}

There’s slight potential for awkwardness since guard is required to exit the scope, of course. But that’s easy to sidestep by putting the whole thing into its own function or method:

func makeABox()
{
    let boxSize = .large

    self.fixupOnPreOS8()

    self.drawBox(sized: boxSize)
}

func fixupOnPreOS8()
{
    guard #available(iOS 8, *) else {
        // Fix up
        return
    }
}

which is really easy to remove when you drop support for the earlier system.

Seems it’s the best solution, before Swift2 you had to use other methods such as using ready-to-use classes wrote by individuals. But that’s fine, you can set a variable in viewDidLoad() and use it to detect the older devices:

var isNewerThan8: Bool = false

func viewDidLoad(){
   if #available(iOS 8.0, *) { 
      isNewerThan8 = true
   } else { 
      isNewerThan8 = false
   }
}

func myFunction(){
   if isNewerThan8 {
     //foo
   }else{
    //boo
   }
}

It is not possible to have logic around the #available statement.

Indeed, the statement is used by the compiler to infer what methods can be called within the scope it embraces, hence nothing can be done at runtime that would conditionally execute the block.

It is possible though to combine conditions, using a comma, as follows

if #available(iOS 8.0, *), myNumber == 2 {
  // some code
}