Number of days between two NSDates

16 Solutions Collect From Internet About “Number of days between two NSDates”

Here’s an implementation I used to determine the number of calendar days between two dates:

+ (NSInteger)daysBetweenDate:(NSDate*)fromDateTime andDate:(NSDate*)toDateTime
    NSDate *fromDate;
    NSDate *toDate;

    NSCalendar *calendar = [NSCalendar currentCalendar];

    [calendar rangeOfUnit:NSCalendarUnitDay startDate:&fromDate
        interval:NULL forDate:fromDateTime];
    [calendar rangeOfUnit:NSCalendarUnitDay startDate:&toDate
        interval:NULL forDate:toDateTime];

    NSDateComponents *difference = [calendar components:NSCalendarUnitDay
        fromDate:fromDate toDate:toDate options:0];

    return [difference day];


Fantastic solution above, here’s Swift version below as an extension on NSDate:

extension NSDate {
  func numberOfDaysUntilDateTime(toDateTime: NSDate, inTimeZone timeZone: NSTimeZone? = nil) -> Int {
    let calendar = NSCalendar.currentCalendar()
    if let timeZone = timeZone {
      calendar.timeZone = timeZone

    var fromDate: NSDate?, toDate: NSDate?

    calendar.rangeOfUnit(.Day, startDate: &fromDate, interval: nil, forDate: self)
    calendar.rangeOfUnit(.Day, startDate: &toDate, interval: nil, forDate: toDateTime)

    let difference = calendar.components(.Day, fromDate: fromDate!, toDate: toDate!, options: [])

A bit of force unwrapping going on which you may want to remove depending on your use case.

The above solution also works for time zones other than the current time zone, perfect for an app that shows information about places all around the world.

Here’s the best solution I’ve found. Seems to utilize the Apple approved method for determining any amount of units between NSDates.

- (int)daysBetween:(NSDate *)dt1 and:(NSDate *)dt2 {
    NSUInteger unitFlags = NSDayCalendarUnit;
    NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; 
    NSDateComponents *components = [calendar components:unitFlags fromDate:dt1 toDate:dt2 options:0];
    return [components day]+1;

E.g. if you want months as well, then you could include ‘NSMonthCalendarUnit’ as a unitFlag.

To credit the original blogger, I found this info here (although there was a slight mistake that I’ve fixed above):

Swift 3.0 Update

extension Date {

    func differenceInDaysWithDate(date: Date) -> Int {
        let calendar = Calendar.current

        let date1 = calendar.startOfDay(for: self)
        let date2 = calendar.startOfDay(for: date)

        let components = calendar.dateComponents([.day], from: date1, to: date2)
        return ?? 0

Swift 2.0 Update

extension NSDate {

    func differenceInDaysWithDate(date: NSDate) -> Int {
        let calendar: NSCalendar = NSCalendar.currentCalendar()

        let date1 = calendar.startOfDayForDate(self)
        let date2 = calendar.startOfDayForDate(date)

        let components = calendar.components(.Day, fromDate: date1, toDate: date2, options: [])


Original Solution

Another solution in Swift.

If your purpose is to get the exact day number between two dates, you can work around this issue like this:

// Assuming that firstDate and secondDate are defined
// ...

var calendar: NSCalendar = NSCalendar.currentCalendar()

// Replace the hour (time) of both dates with 00:00
let date1 = calendar.startOfDayForDate(firstDate)
let date2 = calendar.startOfDayForDate(secondDate)

let flags = NSCalendarUnit.DayCalendarUnit
let components = calendar.components(flags, fromDate: date1, toDate: date2, options: nil)  // This will return the number of day(s) between dates

I use this as category method for NSDate class

// returns number of days (absolute value) from another date (as number of midnights beween these dates)
- (int)daysFromDate:(NSDate *)pDate {
    NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
    NSInteger startDay=[calendar ordinalityOfUnit:NSCalendarUnitDay
                                          forDate:[NSDate date]];
    NSInteger endDay=[calendar ordinalityOfUnit:NSCalendarUnitDay
    return abs(endDay-startDay);

I needed the number of days between two dates including the beginning day.
e.g. days between 14-2-2012 and 16-2-2012 would produce a result of 3.

+ (NSInteger)daysBetween:(NSDate *)dt1 and:(NSDate *)dt2 {
        NSUInteger unitFlags = NSDayCalendarUnit;
        NSCalendar* calendar = [NSCalendar currentCalendar];
        NSDateComponents *components = [calendar components:unitFlags fromDate:dt1 toDate:dt2 options:0];
        NSInteger daysBetween = abs([components day]);
    return daysBetween+1;

Note that it doesn’t matter in which order you provide the dates. It will always return a positive number.

NSDate *lastDate = [NSDate date];
NSDate *todaysDate = [NSDate date];
NSTimeInterval lastDiff = [lastDate timeIntervalSinceNow];
NSTimeInterval todaysDiff = [todaysDate timeIntervalSinceNow];
NSTimeInterval dateDiff = lastDiff - todaysDiff;

dateDiff will then be the number of second between the two dates. Just divide by the number of seconds in a day.


Brian’s answer while good, only calculates difference in days in terms of 24h chunks, but not calendar day differences. For example 23:59 on Dec 24th is only 1 minute away from Christmas Day, for the purpose of many application that is considered one day still. Brian’s daysBetween function would return 0.

Borrowing from Brian’s original implementation and beginning/end of day, I use the following in my program:
(NSDate beginning of day and end of day)

- (NSDate *)beginningOfDay:(NSDate *)date
    NSCalendar *cal = [NSCalendar currentCalendar];
    NSDateComponents *components = [cal components:( NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit ) fromDate:date];
    [components setHour:0];
    [components setMinute:0];
    [components setSecond:0];
    return [cal dateFromComponents:components];

- (NSDate *)endOfDay:(NSDate *)date
    NSCalendar *cal = [NSCalendar currentCalendar];
    NSDateComponents *components = [cal components:( NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit ) fromDate:date];
    [components setHour:23];
    [components setMinute:59];
    [components setSecond:59];
    return [cal dateFromComponents:components];

- (int)daysBetween:(NSDate *)date1 and:(NSDate *)date2 {
    NSDate *beginningOfDate1 = [self beginningOfDay:date1];
    NSDate *endOfDate1 = [self endOfDay:date1];
    NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
    NSDateComponents *beginningDayDiff = [calendar components:NSDayCalendarUnit fromDate:beginningOfDate1 toDate:date2 options:0];
    NSDateComponents *endDayDiff = [calendar components:NSDayCalendarUnit fromDate:endOfDate1 toDate:date2 options:0];
    if ( > 0)
    else if ( < 0)
    else {
        return 0;

Another approach:

NSDateFormatter* dayFmt = [[NSDateFormatter alloc] init];
[dayFmt setTimeZone:<whatever time zone you want>];
[dayFmt setDateFormat:@"g"];
NSInteger firstDay = [[dayFmt stringFromDate:firstDate] integerValue];    
NSInteger secondDay = [[dayFmt stringFromDate:secondDate] integerValue];
NSInteger difference = secondDay - firstDay;

Has the advantage over the timeIntervalSince... scheme that timezone can be taken into account, and there’s no ambiguity with intervals a few seconds short or long of one day.

And a bit more compact and less confusing than the NSDateComponents approaches.

Just adding an answer for those who visit this page trying to do this in Swift. The approach is pretty much the same.

private class func getDaysBetweenDates(startDate:NSDate, endDate:NSDate) -> NSInteger {

    var gregorian: NSCalendar = NSCalendar.currentCalendar();
    let flags = NSCalendarUnit.DayCalendarUnit
    let components = gregorian.components(flags, fromDate: startDate, toDate: endDate, options: nil)


This answer was found here, in the discussion section of the following method:


Here is an implementation of Brian’s function in Swift:

class func daysBetweenThisDate(fromDateTime:NSDate, andThisDate toDateTime:NSDate)->Int?{

    var fromDate:NSDate? = nil
    var toDate:NSDate? = nil

    let calendar = NSCalendar.currentCalendar()

    calendar.rangeOfUnit(NSCalendarUnit.DayCalendarUnit, startDate: &fromDate, interval: nil, forDate: fromDateTime)

    calendar.rangeOfUnit(NSCalendarUnit.DayCalendarUnit, startDate: &toDate, interval: nil, forDate: toDateTime)

    if let from = fromDate {

        if let to = toDate {

            let difference = calendar.components(NSCalendarUnit.DayCalendarUnit, fromDate: from, toDate: to, options: NSCalendarOptions.allZeros)


    return nil

Do you mean calendar days or 24-hour periods? i.e. is Tuesday at 9PM a day before Wednesday at 6AM, or less than one day?

If you mean the former, it’s a bit complicated and you’ll have to resort to manipulations via NSCalendar and NSDateComponent which I don’t recall off the top of my head.

If you mean the latter, just get the dates’ time intervals since the reference date, subtract one from the other, and divide by 24 hours (24 * 60 * 60) to get the approximate interval, leap seconds not included.

Got one, not sure it’s exactly what you want, but it could help some of you, (helped me!!)

My goal was to know if, between two date (less than 24h difference) i had a “overday” day+1:

i did the following (a bit archaic i admit)

NSDate *startDate = ...
NSDate *endDate = ...

NSDate already formatted by another NSDateFormatter (this one is just for this purpose 🙂

NSDateFormatter *dayFormater = [[NSDateFormatter alloc]init];
[dayFormater setDateFormat:@"dd"];

int startDateDay = [[dayFormater stringFromDate:startDate]intValue];

int endDateDay = [[dayFormater stringFromDate:dateOn]intValue];

if (endDateDay > startDateDay) {
} else {
    NSLog(@"same day");

maybe something like this already exist, but didn’t find it


Why not just:

int days = [date1 timeIntervalSinceDate:date2]/24/60/60;

The solution I found was:

+(NSInteger)getDaysDifferenceBetween:(NSDate *)dateA and:(NSDate *)dateB {

  if ([dateA isEqualToDate:dateB]) 
    return 0;

  NSCalendar * gregorian = 
        [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];

  NSDate * dateToRound = [dateA earlierDate:dateB];
  int flags = (NSYearCalendarUnit | NSMonthCalendarUnit |  NSDayCalendarUnit);
  NSDateComponents * dateComponents = 
         [gregorian components:flags fromDate:dateToRound];

  NSDate * roundedDate = [gregorian dateFromComponents:dateComponents];

  NSDate * otherDate = (dateToRound == dateA) ? dateB : dateA ;

  NSInteger diff = abs([roundedDate timeIntervalSinceDate:otherDate]);

  NSInteger daysDifference = floor(diff/(24 * 60 * 60));

  return daysDifference;

Here I am effectively rounding the first date to start from the beginning of the day and then calculating the difference as Jonathan is suggesting above…

I have published an open-source class/library to do just this.

Have a look at RelativeDateDescriptor, which can be used to obtain the time difference as follows…

RelativeDateDescriptor *descriptor = [[RelativeDateDescriptor alloc] initWithPriorDateDescriptionFormat:@"%@ ago" postDateDescriptionFormat:@"in %@"];

// date1: 1st January 2000, 00:00:00
// date2: 6th January 2000, 00:00:00
[descriptor describeDate:date2 relativeTo:date1]; // Returns '5 days ago'
[descriptor describeDate:date1 relativeTo:date2]; // Returns 'in 5 days'

Why note use the following NSDate method:

- (NSTimeInterval)timeIntervalSinceDate:(NSDate *)anotherDate

This will return the number of seconds between your two dates and you can divide by 86,400 to get the number of days !!